MathML

$$=\frac{2^{20}+{\left(2^2\right)}^{10}+{\left(2^2\right)}^{11}+{\left(2^3\right)}^8}{2^{21}+{\left(2^3\right)}^7+{\left(2^2\right)}^{12}}=\frac{2^{20}+2^{20}+2^{22}+2^{24}}{2^{21}+2^{21}+2^{24}}=\frac{\bcancel{2^{20}}\left(1+1+4+16\right)}{\bcancel{2^{20}}\left(2+2+16\right)}=\frac{22}{20}=\frac{11}{10}$$