MathML

$$=\frac{2^{20}+{\left(2^2\right)}^{10}+{\left(2^2\right)}^{11}+{\left(2^3\right)}^8}{2^{21}+{\left(2^3\right)}^7+{\left(2^2\right)}^{12}}$$ $$=\frac{2^{20}+2^{20}+2^{22}+2^{24}}{2^{21}+2^{21}+2^{24}}$$ $$=\frac{\bcancel{2^{20}}(1+1+4+16)}{\bcancel{2^{20}}(2+2+16)}$$ $$=\frac{22}{20}$$ $$=\frac{11}{10}$$